Question

Find the equation of a line making an angle of ${60}^{\circ }$ with the positive direction of $X$-axis and having a $y$-intercept $3$ units

Answer 1

Given that :

Slope $=m=tan{60}^{\circ }=\sqrt{3}$

$y$-intercept $=c=3$

Solution:

Equation of a straight line, $y=mx+c$

i.e. $y=\sqrt{3}x+3$

Therefore, $y=\sqrt{3}x+3$ is the required equation of the line.