Question

Find the equation of a line that has y-intercept-4 and is parallel to the line joining (2, -5) and (1, 2).

Answer 1

$\text{Here, y intercept, c = - 4}\text{The required line is parallel to line joining}(2,-5)and(1,2)\text{Let m be the slope of the required line, then}\text{m = slope of (2, -5) and (1, 2)}m=\frac{y_2-y_1}{x_2-x_1}=\frac{2-(-5)}{1-2}=\frac{7}{-1}=-7\therefore \text{the required equation of line is}y=mx+cy=-7x-47x+y+4=0$