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Question
Find the equation of a line that has y-intercept-4 and is parallel to the line joining (2, -5) and (1, 2).
Find the equation of a line that has y-intercept-4 and is parallel to the line joining (2, -5) and (1, 2).
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Solution
Here, y intercept, c = - 4The required line is parallel to line joining(2, −5) and (1, 2)Let m be the slope of the required line, thenm = slope of (2, -5) and (1, 2)m=y2−y1x2−x1=2−(−5)1−2=7−1=−7∴ the required equation of line isy=mx+cy=−7x−47x+y+4=0
Here, y intercept, c = - 4The required line is parallel to line joining(2, −5) and (1, 2)Let m be the slope of the required line, thenm = slope of (2, -5) and (1, 2)m=y2−y1x2−x1=2−(−5)1−2=7−1=−7∴ the required equation of line isy=mx+cy=−7x−47x+y+4=0
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