Find the equation of a line whose $x$ intercept is 8 and passing through the point (4, -8).

$y = 7 x + 35$

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$y = 2 x - 16$

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$y = 2 x + 16$

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$y = 7 x + 30$

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Solution

The correct option is B
$y = 2 x - 16$

Given : $x$ intercept = 8
$∴ i t s c o o r d i n a t e s (x, y) = (8, 0)$

Slope of the line passing through points (8,0) and (4, -8) is,

Slope $= \frac{y_{2} - y_{1}}{x_{2} - x_{1}} = \frac{0 + 8}{8 - 4} = \frac{8}{4}$
$∴ m = 2$
Equation of straight line passing through point (8,0) and slope = 2 is,
$y - y_{1} = m (x - x_{1})$
$\Rightarrow y - 0 = 2 (x - 8)$
$\Rightarrow y = 2 x - 16$

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Find the equation of the line, whose :

(i) x-intercept = 5 and y-intercept = 3

(ii) x-intercept = -4 and y-intercept = 6

(iii) x-intercept = -8 and y-intercept = -4

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