Question

Find the equation of the straight line passing through $(-3,2)$ and having slope $\frac{-5}{3}$

Answer 1

Given:Slope$=\frac{-5}{3}$

Point is $(-3,2)$

Equation of the line is $y-y_1=m(x-x_1)$

$y-2=\frac{-5}{3}(x+3)$

$\Rightarrow 3y-6=-5x-15$

$\Rightarrow 3y-6+5x+15=0$

$\therefore$Equation of the line is $5x+3y+9=0$