Question

Find the equation of the straight line passing through $(-3,5)$ and having slope $\frac{-1}{3}$

Answer 1

Given:Slope$=\frac{-1}{3}$

Point is $(-3,5)$

Equation of the line is $y-y_1=m(x-x_1)$

$y-5=\frac{-1}{3}(x+3)$

$\Rightarrow 3y-15=-x-3$

$\Rightarrow 3y-15+x+3=0$

$\therefore$Equation of the line is $x+3y-12=0$