Question

Find the greatest number that will divide 55, 127 and 175 so as to leaves the same remainder in each case

• A. 1
• B. 16
• C. 24
• D. 15

Answer 1

The correct option is C 24

$127-55=72$
$175-127=48$
$175-55=120$
HCF of 72,48,120
$72=2^3\times 3^2$
$48=2^4\times 3$
$120=2^3\times 3\times 5$
$HCF=2^3\times 3=24$
$\therefore Requirednumber=24$