Question

Find the irreducible form of
$4a^2+12a.$

• A. $4a\times (a+4)$
• B. $4\times (a^2+2a)$
• C. $2\times 2\times a(a+2)$
• D. $2\times 2\times a\times (a+3)$

Answer 1

The correct option is D $2\times 2\times a\times (a+3)$

$\text{The given expression}4a^2+12a$
can be factorized as,
$4a^2+12a$
$=(2\times 2\times a\times a)+(2\times 2\times 3\times a)$
$\text{Taking}(2\times 2\times a)\text{, we get}$
$=2\times 2\times a\times (a+3)$
Since the above expression can not be factorized further.
So,
$2\times 2\times a\times (a+3)$ is irreducible
form of $4a^2+12a.$