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Question

Find the largest positive integer that will divide 122,150, and 115 leaving remainder 5,7 and 11 respectively.

A
3
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B
2
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C
13
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D
11
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Solution

The correct option is A 13
As the largest positive integer that will divide 122, 150 and 115 leaves remainder 5, 7 and 11 respectively.
Therefore,
1225=117
1507=143
11511=104
The HCF of 104, 117 and 143 is 13
Hence, the largest number which divides 122, 150 and 115 leaving 5, 7 and 11 as remainders respectively is 13.

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