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Question

Find the LCM of 3y+12,y2−16and y4−64y

A
=3y(y4)(y+4)(y2+4y+16)
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B
=3y(y4)(y+4)(y24y+16)
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C
=3y(y4)(y4)(y2+4y+16)
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D
=3y(y+4)(y+4)(y2+4y+16)
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Solution

The correct option is A =3y(y4)(y+4)(y2+4y+16)
3y+12=3(y+4)
y216=(y+4)(y4)
y464y=y(y364)=y(y4)(y2+4y+16)
LCM of given polynomials =3y(y4)(y+4)(y2+4y+16)

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