Find the LCM of $3 y + 12, y^{2} - 16 a n d y^{4} - 64 y$

= 3 y (y - 4) (y + 4) (y^{2} + 4 y + 16)

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= 3 y (y - 4) (y + 4) (y^{2} - 4 y + 16)

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= 3 y (y - 4) (y - 4) (y^{2} + 4 y + 16)

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= 3 y (y + 4) (y + 4) (y^{2} + 4 y + 16)

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Solution

The correct option is A $= 3 y (y - 4) (y + 4) (y^{2} + 4 y + 16)$
$3 y + 12 = 3 (y + 4)$
$y^{2} - 16 = (y + 4) (y - 4)$
$y^{4} - 64 y = y (y^{3} - 64) = y (y - 4) (y^{2} + 4 y + 16)$
$∴$ LCM of given polynomials $= 3 y (y - 4) (y + 4) (y^{2} + 4 y + 16)$

Suggest Corrections

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