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Question

Find the lowest 4-digit number which when divided by 3,4 or 5 leaves a remainder of 2 in each case.

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Solution

Lowest 4digit number is 1000. LCM of 3,4 and 5 is 60.

Dividing 1000 by 60 we get the remainder 40.

Thus the lowest 4-digit number that exactly divisible by 3,4 and 5 is 1000+(6040)=1020.

Now add the remainder 2 that's required. Thus the answer is 1022.

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