Question

Find the magnetic field B due to a semicircular wire of radius 10.0 cm carrying a current of 5.0 A at its centre of curvature.

Answer 1

Given:
Magnitude of current, I = 5 A
Radius of the semi-circular wire, r = 10 cm
∴ Required magnetic field at the centre of curvature
$$\begin{gathered} B=\frac{1}{2}\times \frac{{\mathrm{\mu }}_{0}i}{2r} \\ ={10}^{-7}\times \frac{5}{10\times {10}^{-2}} \\ =5\mathrm{\pi }\times {10}^{-6} \\ =1.6\times {10}^{-5}\mathrm{T} \end{gathered}$$