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Question

Find the maximum value of F such that the system is moving together. Take g=10 m/s2.

A
200 N
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B
150 N
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C
100 N
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D
50 N
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Solution

The correct option is B 150 N
m1=20 kg; m2=10 kg
Taking system as both blocks, we know that by the formula,
F=(m1+m2)(μ1g+as)=(m1+m2)as and we know that as=μ2g
Since (μ1=0)
Fmax=(m1+m2)μ2g=(10+20)(0.5)10=150 N

Alternately:
At just sliding condition, limiting friction f=0.5×10×10=50 N is acting.

F50=20a (1)
f=10a (2)
50=10a
a=5 m/s2
Hence, F=50+20×5=150 N
Fmax=150 N.

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