Find the mean of the following distribution-array - c - c - WlineClass interval Frequency lilhline 0-10 10 110-20 6 120-30 81130-40 12 lI40-50 5 Whline-endarray -4 MARKS-

Formula: 2 Marks Solution: 2 Marks [ Class amp; Class mark amp; Frequency amp; fx; interval amp; (x) amp; (f) ...

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Standard X

Mathematics

Average(Mean)

Find the mean...

Question

Find the mean of the following distribution:
$\begin{matrix} C l a s s i n t e r v a l & F r e q u e n c y 0 - 10 & 10 10 - 20 & 6 20 - 30 & 8 30 - 40 & 12 40 - 50 & 5 \end{matrix}$ [4 MARKS]

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Solution

Formula: 2 Marks
Solution: 2 Marks

$\begin{matrix} C l a s s & C l a s s m a r k & F r e q u e n c y & f x i n t e r v a l & (x) & (f) 0 - 10 & 5 & 10 & 50 10 - 20 & 15 & 6 & 90 20 - 30 & 25 & 8 & 200 30 - 40 & 35 & 12 & 420 40 - 50 & 45 & 5 & 225 \sum f = 41 & \sum f x = 985 \end{matrix}$
$∴$ Mean, $\frac{\sum f x}{\sum f} = \frac{985}{41} = 24.02 (a p p x .)$

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Find the mean of the following distribution: Class intervalFrequency0−101010−20620−30830−401240−505 [4 MARKS]

Formula: 2 Marks Solution: 2 Marks ClassClass markFrequencyfxinterval(x)(f)0−105105010−201569020−3025820030−40351242040−50455225∑f=41∑fx=985 ∴ Mean, ∑fx∑f=98541=24.02(appx.)

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$\begin{matrix} C l a s s i n t e r v a l & F r e q u e n c y 0 - 10 & 10 10 - 20 & 6 20 - 30 & 8 30 - 40 & 12 40 - 50 & 5 \end{matrix}$ [4 MARKS]