Question

Find the no. of ways in which 15 players can be equally divided into three groups

• A.
• B.
• C.
• D.

Answer 1

The correct option is A

The no. of ways in which mn different things can be divided equally into m groups containing n things each =$\left[\frac{(mn!)}{(n!{)}^m}\right]\left(\frac{1}{m!}\right)$

So, required no. of ways = $\left[\frac{(15!)}{(5!{)}^3}\right]\left(\frac{1}{3!}\right)$

We divide by$3!$ Since the groups are of equal size and hence, indistinguishable.