Find the number of molecules having two lone pair of electrons on central atom.
$I_{3}^{-}, X e F_{2}, X e F_{4}, H_{2} O, N H_{2}^{-} H_{2} S, H_{2} S O_{4}, N F_{3}$

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Solution

$X e F_{4}, H_{2} O, N H_{2}^{-}, H_{2} S$
$I_{3}^{-}$
Number of lone pairs = 3
Number of bond pairs = 2
Hybridisation = $s p^{3} d$

$X e F_{2}$
Number of lone pairs = 3
Number of bond pairs = 2
Hybridisation = $s p^{3} d$

$X e F_{4}$
Number of lone pairs = 2
Number of bond pairs = 4
Hybridisation = $s p^{3} d^{2}$

$H_{2} O$
Number of lone pairs = 2
Number of bond pairs = 2
Hybridisation = $s p^{3}$

$N H_{2}^{-}$
Number of lone pairs = 2
Number of bond pairs = 2
Hybridisation = $s p^{3}$

$H_{2} S = s p^{3}$
Number of lone pairs = 2
Number of bond pairs = 2
Hybridisation = $s p^{3}$

$H_{2} S O_{4}$
Number of lone pairs = 0
Number of bond pairs = 4
Hybridisation = $s p^{3}$

$N F_{3}$
Number of lone pairs = 1
Number of bond pairs = 3
Hybridisation = $s p^{3}$

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