Find the number of square tiles of size $5 c m$ required for covering the floor of a room $15 m$ long and $6 m$ wide. Find the cost of the tiles required if one tile costs $₹ 3.50$ .

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Solution

Step 1: Finding the area of a square tile and floor of the room
Side of a square tile $= 5 c m$
Area of a square tile $= s i d e \times s i d e$
$= 5 \times 5$
$= 25 s q c m$
Length of the floor of a room $= 15 m = 1500 c m (1 m = 100 c m)$
Breadth of the floor of a room $= 6 m = 600 c m$
Area of the floor of a room
$= l e n g t h \times b r e a d t h = 1500 \times 600 = 900000 s q c m$
Step 2: Finding number of tiles
Number of tiles
$= \frac{A r e a o f t h e f l o o r o f a r o o m}{A r e a o f a s q u a r e t i l e} = \frac{900000}{25} = 36000$
Step 3: Cost of the tiles required for flooring
Cost of one tile is $₹ 3.50$
Cost of tiles required for flooring
$= \cos t o f o n e t i l e \times n u m b e r o f t i l e s = ₹ 3.50 \times 36000 = ₹ 126000$
So, the number of tiles required for flooring is $36, 000$ and cost of the tiles required is $₹ 1, 26, 000$ .

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Find the number of square tiles of size 5cm required for covering the floor of a room15m long and 6m wide. Find the cost of the tiles required if one tile costs ₹3.50.

Find the number of square tiles of size $5 c m$ required for covering the floor of a room $15 m$ long and $6 m$ wide. Find the cost of the tiles required if one tile costs $₹ 3.50$ .