Question

Find the number of square tiles of size $5cm$ required for covering the floor of a room$15m$ long and $6m$ wide. Find the cost of the tiles required if one tile costs $₹3.50$.

Answer 1

Step 1: Finding the area of a square tile and floor of the room

Side of a square tile$=5cm$

Area of a square tile$=side\times side$

$=5\times 5$

$=25sqcm$

Length of the floor of a room $=15m=1500cm(1m=100cm)$

Breadth of the floor of a room$=6m=600cm$

Area of the floor of a room

$$\begin{gathered} =length\times breadth \\ =1500\times 600 \\ =900000sqcm \end{gathered}$$

Step 2: Finding number of tiles

Number of tiles
$$\begin{gathered} =\frac{Areaofthefloorofaroom}{Areaofasquaretile} \\ =\frac{900000}{25} \\ =36000 \end{gathered}$$

Step 3: Cost of the tiles required for flooring

Cost of one tile is $₹3.50$

Cost of tiles required for flooring

$$\begin{gathered} =\cos tofonetile\times numberoftiles \\ =₹3.50\times 36000 \\ =₹126000 \end{gathered}$$

So, the number of tiles required for flooring is $36,000$ and cost of the tiles required is $₹1,26,000$.