Find the oxidation number of $S$ in ${H S O_{3}}^{-}$ ion.

Open in App

Solution

Let the oxidation number of $S$ be x in $H S O_{3}^{-}$ ion.
We know that, Ox. no. of $H$ $= + 1$
Ox. no. of O $= - 2$
So, Ox. no. $H$ $+$ Ox. no. $S$ $+$ $3$ (Ox. no. $O$ ) $= - 1$
$+ 1 + x + 3 (- 2) = - 1$
or $+ 1 + x - 6 = - 1$
or $x - 5 = - 1$
or $x = + 5 - 1 = + 4$
The oxidation number of $S$ in $H S O_{3}^{-}$ ion is $+ 4$ .

Suggest Corrections

Similar questions

S

{S O_{4}}^{2 -}

M n

[M n O_{4}]^{-}

P t

[P t C l_{6}]^{2 -}

S

F e S_{2}

- 1

F e S_{2}

F e^{+ 2}

(S - S)^{2 -}

S_{2} C l_{2}

Join BYJU'S Learning Program