Find the percentage of water of crystallisation in $C u S O_{4} .5 H_{2} O .$ (At. Mass $C u - 64, H = 1, O = 16, S = 32$ )

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Solution

Molar mass of $C u S O_{4} .5 H_{2} O$ = 159.609 + 90 = ~250

Mass of water of crystallization = 5 18 = 90

Percentage = = 36%.

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[C u S O_{4} .5 H_{2} O]

[C u S O_{4} .5 H_{2} O]

C u S O_{4} .5 H_{2} O \to C u S O_{4} + 5 H_{2} O

C u = 64, S = 32, O = 16, H = 1

C u S O_{4} .5 H_{2} O (H = 1, O = 16, S = 32, C u = 64)

C u S O_{4} .5 H_{2} O

C u

=

H

=

O

=

S

=

M g S O_{4} . 7 H_{2} O

M g = 24, S = 32, O = 16, H = 1]

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