Find the perimeter of a square field whose area is $13689 m^{2}$ .

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Solution

Area $= (s i d e)^{2} = 13689 m^{2}$
side $= \sqrt{13689} m$
$= 3 \times 3 \times 13$
$= 117 m$
$∴$ perimeter $= 4 (s i d e)$
$= 4 \times 117$
$= 468 m$

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Find the perimeter of a square field whose area is 13689m2.

Area =(side)2=13689m2side =√13689m=3×3×13=117m∴ perimeter =4(side)=4×117=468m

Find the perimeter of a square field whose area is $13689 m^{2}$ .

Area $= (s i d e)^{2} = 13689 m^{2}$
side $= \sqrt{13689} m$
$= 3 \times 3 \times 13$
$= 117 m$
$∴$ perimeter $= 4 (s i d e)$
$= 4 \times 117$
$= 468 m$