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Complex Numbers

Find the prin...

Question

Find the principal value of argument of $(1 + i) (- 1 + i)$

π

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0

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2 π

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\frac{π}{2}

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Solution

The correct option is B $0$
$\to (1 + i) (- 1 + i)$
$\to (i + 1) (i - 1)$
$\to i^{2} - 1^{2} = - 1 - 1 = - 2$
Argument $= 0$

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Similar questions

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C o l u m n - I

a r g (z)

c o l u m n - I I

$C o l u m n - I$ (equation in z)	$C o l u m n - I I$ (principal value of arg(z))
$z^{2} - z + 1 = 0$	$- 2 π / 3$
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${2 z}^{2} + 1 + i \sqrt{3} = 0$	$π / 3$
${2 z}^{2} + 1 - i \sqrt{3} = 0$	$2 π / 3$

z = \frac{2 + i}{4 i + {(1 + i)}^{2}},

i = \sqrt{- 1}

z = \frac{(1 + i \sqrt{3})^{2}}{(1 - i)^{3}}

1 - i

- 1 - \sqrt{3 i}

1 + \sqrt{2} + i

z = \frac{(1 + i) (1 + 2 i) (1 + 3 i) \dots \dots \dots (1 + n i)}{(1 - i) (2 - i) (3 - i) \dots \dots \dots (n - i)}

i = \sqrt{- 1}, n \in N

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