Find the remainder if $2 m^{2} - 3 m + 10 = 0$ is divided by $m - 5$

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Solution

$2 m^{2} - 3 m + 10 = 0$

For $m = - 5$

Using remainder theorem,

$2 (- 5)^{2} - 3 (- 5) + 10 = 0$

$= 50 + 15 + 10$

$= 75$

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(2 m^{2} - 3 m + 10) \div (m - 5)

\frac{(2 m^{2} - 3 m - 10)}{(m - 5)}

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When N is divided by X, the remainder is 28. When N is divided by 10X, the remainder is 125. Find the remainder when N is divided by 5X.

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