Question

Find the smallest number which when reduced by 2 is divisible by 5 and 7

• A. 35
• B. 42
• C. 37
• D. 64

Answer 1

The correct option is C 37

To find the smallest no divisible both by 5 and 7, Find their LCM

5 & 7 are co-prime numbers $\therefore$ LCM = 5 $\times$ 7 = 35

LCM = 5 $\times$ 7 = 35

Now, Add 2 to it, so that when we reduce by 2 we get the smallest divisible both by 5 and 7