Question

Find the smallest number which when reduced by 5 is divisible by 3 and 8

• A. 24
• B. 29
• C. 42
• D. 53

Answer 1

The correct option is B 29

To find the smallest number divisible by both 3 and 8 is

Now, add 5 to 24; 5+ 24 = 29

When 29 is reduced by 5 we get 24 which is divisible both by 3 and 8

$\therefore$ 24 + 5 = 29

LCM = 3 $\times 2\times 2\times$ 2 = 24