Question

Find the sum of interior angles of a polygon with 12 sides in degrees.

• A. 1800

Answer 1

The correct option is A 1800

Sum of interior angles of a polygon with n sides $=(n-2)\times {180}^{\circ }$

$\therefore$ Sum of interior angles of a polygon with 12 sides $=(12-2)\times {180}^{\circ }$

$=10\left({180}^{\circ }\right)$

= 1800°