Question

Find the sum of length of the parallel sides of a trapezium whose area is $4.2m^2$ and whose height is $280cm$.

Answer 1

Area of trapezium $=\frac{a+b}{2}\times h$

Where, $a$ and $b$ are parallel sides and $h$ is perpendicular height.

So, $(a+b)$ is sum of length of bases of a trapezium.

Now,

Area of trapezium $=\frac{a+b}{2}\times h$

$\Rightarrow$ $4.2\times {100}^2=\frac{a+b}{2}\times 280$ {$1m=100cm$}

$\Rightarrow$ $\frac{8.4}{280}\times 10000=a+b$

$\Rightarrow$ $a+b=300cm$