Find the surface area of the cuboidal box which is open at the top, if:
l=length of the cuboid,
b=breadth of the cuboid and
h=height of the cuboid
A
Surface Area = 2(lb+bh+lh)
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B
Surface Area = 2lb+2bh+hl
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C
Surface Area = lb+2bh+2hl
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D
Surface Area = 2lb+bh+2hl
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Solution
The correct option is C Surface Area = lb+2bh+2hl
When the cuboidal box is cut open, the total surface area is the sum of the areas of 5 rectangles as shown in the figure.
Surface Area = hl+lb+bh+hl+bh ∴ Surface Area = lb+2bh+2hl