Question

Find the total number of moles of electrons present in $6.022\times {10}^{18}{H}_{3}P{O}_4$ molecules.

• A. 0.5 moles
• B. 0.05 moles
• C. 0.005 moles
• D. 0.0005 moles

Answer 1

The correct option is D 0.0005 moles

$6.022\times {10}^{18}{H}_{3}P{O}_4$ molecules $=\frac{6.022\times {10}^{18}}{6.022\times {10}^{23}}$ moles $={10}^{-5}$ moles of$H_{3}P{O}_4$
The number of electrons in one molecule of $H_{3}P{O}_4=3+15+(8\times 4)=50$electrons.
So, the number of moles of electrons in one mole of $H_{3}P{O}_4=50$ moles.
Therefore, the total number of moles of electrons in ${10}^{-5}$ moles of $H_{3}P{O}_4$ will be
$=50\times {10}^{-5}$ moles $=$ 0.0005 moles