Find the total surface area of a closed box of wood whose dimensions are 2 m, 1.5 m and 80 cm, cost of wood used to make it at the rate of Rs.120.55 per $m^{2}$ .

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Solution

Total surface area $= 2 (l b + b h + h l) = 2 {(2 \times 1.5) + (1.5 \times 0.8) + (0.8 \times 2)} = 11.6 m^{2}$

Volume $= l b h = 0.8 \times 2 \times 1.5 = 2.4 m^{3}$

$C o s t = 120.55 \times v o l u m e = 120.55 \times 2.4 = 289.32$

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Find the total surface area of a closed box of wood whose dimensions are 2 m, 1.5 m and 80 cm, cost of wood used to make it at the rate of Rs.120.55 per m2.

Total surface area =2(lb+bh+hl)=2{(2×1.5)+(1.5×0.8)+(0.8×2)}=11.6m2Volume =lbh=0.8×2×1.5=2.4m3Cost=120.55×volume=120.55×2.4=289.32

Find the total surface area of a closed box of wood whose dimensions are 2 m, 1.5 m and 80 cm, cost of wood used to make it at the rate of Rs.120.55 per $m^{2}$ .

Total surface area $= 2 (l b + b h + h l) = 2 {(2 \times 1.5) + (1.5 \times 0.8) + (0.8 \times 2)} = 11.6 m^{2}$

Volume $= l b h = 0.8 \times 2 \times 1.5 = 2.4 m^{3}$

$C o s t = 120.55 \times v o l u m e = 120.55 \times 2.4 = 289.32$