Find the valency factor of BrO 3-in the reaction BrO 3-6 H -6 e - Br -3 H 2 OA- 5B- 6C- 4D- 2

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Valency and Oxidation State

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Question

Find the valency factor of $B r O_{3}^{-}$ in the reaction $B r O_{3}^{-} + 6 H^{+} + 6 e^{-} + \to B r^{-} + 3 H_{2} O$

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B r O_{3}^{-} + 6 e^{-} + 6 H^{+} \to B r^{-} + 3 H_{2} O

B r O_{3}^{-}

For the chemical reaction $5 B r^{⊖} + B r O_{3}^{⊖} + 6 H^{\oplus} \to 3 B r_{2} + 3 H_{2} O$

Rate = $k [B r^{⊖}] [B r O_{3}^{⊖}] [H^{\oplus}]^{2}$ The order of reaction with respect to $[B r^{⊖}]$ is:

For the chemical reaction $5 B r^{⊖} + B r O_{3}^{⊖} + 6 H^{\oplus} \to 3 B r_{2} + 3 H_{2} O$

Rate = $k [B r^{⊖}] [B r O_{3}^{⊖}] [H^{\oplus}]^{2}$ The molecularity and order of reaction with respect to $[B r^{⊖}]$ is:

B r O_{3}^{-} (a q) + 5 B r^{-} (a q) + 6 H^{+} \to 3 B r_{2} (l) + 3 H_{2} O (l)

\frac{d [B r_{2}]}{d t} = k [B r^{-}] [B r O_{3}] [H^{+}]^{2}

- \frac{d [B r^{-}]}{d t} = k^{'} [B r^{-}] [B r O_{3}] [H^{+}]^{2}

B r O_{3}^{-} + 6 H^{+} + 6 e^{-} \to B r^{-} + 3 H_{2} O

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