Find the value.
3×6÷2+4−3=?
According to BODMAS, Division precedes Multiplication, which precedes Addition, and after that follows Subtraction.
Hence, 6÷2=3
Then, 3×3=9
Followed by, 9+4=13
And finally 13−3=10
Find the value of [(3+4–6÷2+2)+(9÷3+6×5)÷11].