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Question

Find the value of (103)2 using algebraic identities.


A

10609

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B

10906

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C

10069

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D

16009

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Solution

The correct option is A

10609


We need to find the square of 103. For that, we split it into 2 numbers whose squares are easy to calculate.

Hence, we write (103)2 as (100+3)2.

We have (a+b)2=a2+b2+2ab

Comparing it with the above identity, we have a=100,b=3

On expanding, we get (100)2+(3)2+2(100)(3)=10000+9+600=10609


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