Find the value of:
$36 x^{2} + 49 y^{2} + 84 x y$ , when $x = 3, y = 6$

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Solution

$36 x^{2} + 49 y^{2} + 84 x y$

Substituting values of $x, y$ we get

$\Rightarrow 36 (3)^{2} + 49 (6)^{2} + 84 (3) (6)$

$\Rightarrow 324 + 1764 + 1512 = 3600$

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36 x^{2} + 49 y^{2} + 84 x y

x = \frac{1}{4}, y = \frac{2}{7}

Find the value of the expression $(36 x^{2} + 25 y^{2} - 60 x y)$ when $x = \frac{5}{6}$ and $y = \frac{1}{5}$ .

16 x^{2} + 25 y^{2} + 40 x y

x = 3, y = 6

9 x^{2} + 49 y^{2} - 42 x y

x = 15

y = 3

9 x^{2} + 49 y^{2} - 42 x y

x = 15

y = 3

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