Question

Find the value of $△$ BAC in the given figure.

• A. 58°
• B. 44°
• C. 55°
• D. 65°

Answer 1

The correct option is B

44°

In a triangle, exterior angle is equal to sum of interior opposite angles.

Therefore, $△$ ACD = $△$ ABC + $△$ BAC

6$x$ – 7 = 2$x$ + 103 - $x$

6$x$ – 7 = $x$ + 103

6$x$ – $x$ = 103 + 7

5$x$ = 110°

$x$ = $\frac{110}{5}$

$x$ = 22°

If $x$ = 25°^, then $\angle$ BAC = 2 $\times$ 22 = 44°.