Question

Find the value of $x$, if $10000x=(9982{)}^2-{\left(18\right)}^2$.

Answer 1

$10000x={\left(9982\right)}^2-{\left(18\right)}^2$

we know that,

$\Rightarrow a^2-b^2=(a+b)(a-b).....\left(1\right)$

using equation $\left(1\right)$ we get

$\Rightarrow 10000x=(9982+18)(9982-18)$

$\Rightarrow 10000x=10000\left(9964\right)$

$\Rightarrow x=\frac{10000}{10000}\left(9964\right)$

$\Rightarrow x=9964$

Hence, the answer is $9964$