Question

Find the value of $x$ in $\frac{-x}{3}+8=\frac{9}{13}$

• A. $\frac{-13}{285}$
• B. $\frac{13}{285}$
• C. $\frac{-285}{13}$
• D. $\frac{285}{13}$

Answer 1

Answer: (D)

$\frac{285}{13}$

$\frac{-x}{3}+8=\frac{9}{13}$

$\therefore -\frac{x}{3}=\frac{9}{13}-8$

$⟹\frac{-x}{3}=\frac{9-104}{13}$

$⟹\frac{-x}{3}=\frac{-95}{13}$

Multiplying both sides by $(-3)$
$⟹\frac{-x}{3}\times (-3)=\frac{-95}{13}\times (-3)$

$\therefore x=\frac{285}{13}$