Question

Find the volume in cubic metre (cu. m) of each of the cuboids whose dimensions are:
(i) length = 12 m, breadth = 10 m, height = 4.5 cm
(ii) length = 4 m, breadth = 2.5 m, height = 50 cm.
(iii) length = 10 m, breadth = 25 dm, height = 50 cm.

Answer 1

$$\begin{gathered} \left(\mathrm{i}\right) \\ \mathrm{Length}=12\mathrm{m} \\ \mathrm{Breadth}=10\mathrm{m} \\ \mathrm{Height}=4.5\mathrm{m} \\ \therefore \mathrm{Volume}\mathrm{of}\mathrm{the}\mathrm{cubo}\mathrm{id}=\mathrm{length}\times \mathrm{breadth}\times \mathrm{height} \\ =12\times 10\times 4.5 \\ =540{\mathrm{m}}^3 \\ \left(\mathrm{ii}\right) \\ \mathrm{Length}=4\mathrm{m} \\ \mathrm{Breadth}=2.5\mathrm{m} \\ \mathrm{Height}=50\mathrm{cm} \\ =\frac{50}{100}\mathrm{m}(\because 1\mathrm{m}=100\mathrm{cm}) \\ =0.5\mathrm{m} \\ \therefore \mathrm{Volume}\mathrm{of}\mathrm{the}\mathrm{cub}\mathrm{oid}=\mathrm{length}\times \mathrm{breadth}\times \mathrm{height} \\ =4\times 2.5\times 0.5 \\ =5{\mathrm{m}}^3 \\ \left(\mathrm{iii}\right) \\ \mathrm{Length}=10\mathrm{m} \\ \mathrm{Breadth}=25\mathrm{dm} \\ =\frac{25}{10}\mathrm{m}(\because 10\mathrm{dm}=1\mathrm{m}) \\ =2.5\mathrm{m} \\ \mathrm{Height}=25\mathrm{cm}=\frac{25}{100}\mathrm{m}=0.25\mathrm{m} \\ \therefore \mathrm{Volume}\mathrm{of}\mathrm{the}\mathrm{cub}\mathrm{oid}=\mathrm{length}\times \mathrm{breadth}\times \mathrm{height} \\ =10\times 2.5\times 0.25 \\ =6.25{\mathrm{m}}^3 \end{gathered}$$