Find the weight of solid rectangular iron piece of size 50 cm × 40 cm × 10cm, if 1 cm³ of iron weighs 8 gm.

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Solution

$The dimension of the rectangular piece of iron is 50 cm \times 40 cm \times 10 cm . i . e ., volume = 50 cm \times 40 cm \times 10 cm = 20000 {cm}^{3} It is given that the weight of 1 {cm}^{3} of iron is 8 gm . ∴ The weight of the given piece of iron = 20000 \times 8 gm = 160000 gm = 160 \times 1000 gm = 160 kg (∵ 1 kg = 1000 gm)$

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Find the weight of solid rectangular iron piece of size 50 cm × 40 cm × 10cm, if 1 cm3 of iron weighs 8 gm.

The dimension of the rectangular piece of iron is 50 cm×40 cm×10 cm.i.e., volume = 50 cm×40 cm×10 cm=20000 cm3It is given that the weight of 1 cm3 of iron is 8 gm. ∴ The weight of the given piece of iron =20000×8 gm =160000 gm =160×1000 gm =160 kg (∵ 1 kg=1000 gm)

Find the weight of solid rectangular iron piece of size 50 cm × 40 cm × 10cm, if 1 cm³ of iron weighs 8 gm.