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Question

Find three concscutive whole number whose sum is more than 45 but less then 54

A
16,20,18
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B
16,19,18
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C
15,17,18
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D
16,17,18
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Solution

The correct option is D 16,17,18

Let consecutive whole number be x,x+,x+2

(x)+(x+1)+(x+2)>45 [Sum will be greater than 45]

3x+3>45

x>14


(x)+(x+1)+(x+2)<54 [Sum will be less than 54 ]

3x+3<54
x<17

So, x will lie between 14 and 17

Take x=16,x+1=17, and x+2=18

16+17+18=51

Sum of the above is lying between 45 and 54.

According to the option, D will be the correct one i.e 16, 17, and 18 are the three consecutive whole numbers.



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