Find three concscutive whole number whose sum is more than 45 but less then 54
The correct option is D 16,17,18
Let consecutive whole number be x,x+,x+2
(x)+(x+1)+(x+2)>45 [Sum will be greater than 45]
⇒3x+3>45
⇒x>14
(x)+(x+1)+(x+2)<54 [Sum will be less than 54 ]
So, x will lie between 14 and 17
Take x=16,x+1=17, and x+2=18
16+17+18=51
Sum of the above is lying between 45 and 54.
According to the option, D will be the correct one i.e 16, 17, and 18 are the three consecutive whole numbers.