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Chelation

Following che...

Question

Following chemical species were reported for water sample from a well

$\begin{matrix} Species & Concentration (milliequivalent/L) Chloride (C l^{-}) & 15 Sulphate (S O_{4}^{2 -}) & 15 Carbonate (C O_{3}^{2 -}) & 05 Bicarbonate (H C O_{3}^{-}) & 13 Calcium (C a^{2 +}) & 12 Magnesium (M g^{2 +}) & 18 p H & 8.5 \end{matrix}$ Total hardness in $m g / L a s C a C O_{3}$ is

2000

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1500

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3000

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5000

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Solution

The correct option is B $1500$
Total hardness is due to multivalent cations $(C a^{2 +}, M g^{2 +})$
Total harndess $=$ milliequivalent of $C a^{2 +}$ $+$ milliequivalent of $M g^{2 +}$
$= 12 + 18$
$= 30$ milliequivalent/L
$= 30$ milliequivalent $C a C O_{3}$
$= 30 \times$ equivalent weight of $C a C O_{3}$ $m g / L$
$= 30 \times 50 m g / L$
$= 1500 m g / L a s C a C O_{3}$

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Similar questions

\begin{matrix} Species & Concentration (milliequivalent/L) Chloride (C l^{-}) & 15 Sulphate (S O_{4}^{2 -}) & 15 Carbonate (C O_{3}^{2 -}) & 05 Bicarbonate (H C O_{3}^{-}) & 13 Calcium (C a^{2 +}) & 12 Magnesium (M g^{2 +}) & 18 p H & 8.5 \end{matrix}

m g / L

C a C O_{3}

Species	Concentration (milliequivalent/L)
Chloride $(C l^{-})$	15
Sulphate $(S O_{4}^{2 -})$	15
Carbonate $(C O_{3}^{2 -})$	05
Bicarbonate $(H C O_{3}^{-})$	30
Calcium $(C a^{2 +})$	12
Magnesium $(M g^{2 +})$	18
$p H$	8.5

C a C O_{3}

Following chemical species were reported for water sample from a well

Species	Concentration (milliequivalent/L)
Chloride $(C l^{-})$	15
Sulphate $(S O_{4}^{2 -})$	15
Carbonate $(C O_{3}^{2 -})$	05
Bicarbonate $(H C O_{3}^{-})$	30
Calcium $(C a^{2 +})$	12
Magnesium $(M g^{2 +})$	18
$p H$	8.5

Alkalinity present in the water in mg/L as $C a C O_{3}$

[N a^{+}] = 38 m g / l, ∣ ∣ C a^{2_{+}} ∣ ∣ = 10 m g / l

[H C O_{3}^{-}] = 183 m g / l, [M g^{2 +}] = 12 m g / l

[C O_{3}^{2 -}] = 30 m g / l, [A l^{3 +}] = 27 m g / l

[S O_{4}^{2 -}] = 45 m g / l

(i n m g / l a s C a C O_{3})

p H = 8.10

Ion	$C a^{2 +}$	$M g^{2 +}$	$N a^{+}$	$H C O_{3}^{-}$	$S O_{4}^{2 -}$	$C l^{-}$
Ion concentration $(m g / L)$	$100$	$6$	$15$	$250$	$45$	$39$
Atomic weight	$C a = 40$	$M g = 24$	$N a = 23$	$H = 1$ $C = 12$ $O = 16$	$S = 32$ $O = 16$	$C l = 35.5$

(m g / L a s C a C O_{3})

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