For a coil, inductive reactance is equal to its resistance, at certain frequency. Then the phase difference between voltage and current in radian is

π/3

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π/6

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π/2

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π/4

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Solution

The correct option is D
π/4

Given $X_{L} = R$
The phase difference is given by
$t a n ϕ = \frac{X_{L}}{R} = \frac{R}{R} = 1$
$\Rightarrow ϕ = \frac{π}{4}$

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For a coil, inductive reactance is equal to its resistance, at certain frequency. Then the phase difference between voltage and current in radian is

The correct option is D π/4 Given XL=R The phase difference is given by tanϕ=XLR=RR=1 ⇒ϕ=π4

The correct option is D
π/4

Given $X_{L} = R$
The phase difference is given by
$t a n ϕ = \frac{X_{L}}{R} = \frac{R}{R} = 1$
$\Rightarrow ϕ = \frac{π}{4}$