Question

For a projectile, the ratio of maximum height reached to the square of flight time is (g = 10 m$s^{-2}$)

• A. 5 : 4
• B. 5 : 2
• C. 5 : 1
• D. 10 : 1

Answer 1

The correct option is A 5 : 4

H = $\frac{u^2{sin}^2\theta }{2g}$ and T = $\frac{2usin\theta }{g}$
So $\frac{H}{T^2}$ = $\frac{\frac{u^2{sin}^2\theta }{2g}}{\frac{4u^2{sin}^2\theta }{g^2}}$ = $\frac{g}{8}$ = $\frac{5}{4}$