For a reaction A+B⇋2C, 2 moles of A and 3 moles of B are allowed to react. If equilibrium constant is 4 at 400∘C, then the mole of ′C′ at equilibrium is:
A
1
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B
2.4
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C
3.6
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D
4
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Solution
The correct option is B2.4 According to the given chemical equation, on consumption of one mol each of 'A' and 'B' produces '2' mol of 'C' thus, A+B⇋2C t=o,230 t=teq2−x3−x2x
Now, according to formula, K=[C]2[A][B]⇒4=(2x)2(2−x)(3−x)
On, simplification we get x = 1.2, hence 2x=2×1.2=2.4