For a reaction at equilibrium, the value of Gibbs free energy change is:

> 0

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< 0

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= 0

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\neq

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Solution

The correct option is C = 0
At Equilibrium, $△ G_{r e a c t i o n} = 0$ . However, if $△ G_{r e a c t i o n} > 0$ , then the reaction will be non-spontaneous.
And if $△ G_{r e a c t i o n} < 0$ , then the reaction will be spontaneous.

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