For a reaction,

$A + B \to C + D; Δ H = - 20 K J m o l e^{- 1}$

The activation energy for the forward reaction is 85 $k J$ . Then the activation energy for the backward reaction is:

65 k J

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105 k J

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85 k J

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40 k J

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Solution

The correct option is B $105 k J$
The activation energy for the backward reaction is equal to the sum of the activation energy of the forward reaction and the enthalpy change of the reaction.

The activation energy for the backward reaction $= 85 k J - (- 20) k J = 105 k J .$

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For the reaction $A + B \to C + D Δ H = - 20 k J m o l^{- 1}$ . The activation energy of the forward reaction is $85 k J m o l^{- 1}$ . The activation energy for backward reaction is

Q. For a reaction,

A \to B; Δ H = 20 k J . {m o l}^{- 1}

, the activation energy of the forward reaction is

85 k J / m o l

. The activation energy of the backward reaction will be:

For the reaction $A + B \to C + D Δ H = - 20 k J m o l^{- 1}$ . The activation energy of the forward reaction is $85 k J m o l^{- 1}$ . The activation energy for backward reaction is