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Byju's Answer
Standard XII
Chemistry
Arrhenius Equation
For a reactio...
Question
For a reaction, the overall rate constant is related to individual rate constants by :
A
k
=
k
1
−
k
2
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B
k
1
/
k
2
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C
k
1
k
2
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D
k
1
+
k
2
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Solution
The correct option is
D
k
1
+
k
2
−
d
a
d
t
=
k
1
[
A
]
+
k
2
[
A
]
=
(
k
1
+
k
2
)
[
A
]
=
k
[
A
]
Overall rate constant=k=
k
1
+
k
2
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0
Similar questions
Q.
For a Ist order decomposition of A as given
Therefore rate constant (K) for the overall decomposition of A is
Q.
A reaction takes place in three steps having rate constants
K
1
,
K
2
,
K
3
respectively. The overall rate constant
K
=
K
1
K
3
K
2
. If energies of activation for the three steps 40, 30, 20 kJ respectively, the overall energy of activation is:
Q.
A reaction can take place by two paths.
k
1
and
k
2
are rate constants for the two paths &
E
1
and
E
2
are their respective activation energies.
At temperature
T
a
:
k
1
>
k
2
,
E
1
<
E
2
Its temperature is raised to
T
b
, the rate constants change to
k
′
1
&
k
′
2
. Which relation is correct between
k
1
,
k
2
,
k
′
1
&
k
′
2
(considering activation energy does not change with temperature)?
Q.
A reaction takes place in three steps with an individual rate constant and activation energy, as given below.
Rate constant Activation energy
Step 1
k
1
E
a
1
=
180
k
J
/
m
o
l
Step 2
k
2
E
a
2
=
80
k
J
/
m
o
l
Step 3
k
3
E
a
3
=
50
k
J
/
m
o
l
And overall rate constant,
k
=
(
k
1
k
2
k
3
)
2
/
3
.
The overall activation energy of the reaction will be:
Q.
For the hypothetical reaction, the equilibrium constant (k) values are given
A
→
B
(
k
=
k
1
)
B
→
C
(
k
=
k
2
)
C
→
D
(
k
=
k
3
)
What is the value of equilibrium constant for
A
→
D
?
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