Question

For $AB$ bond if percent ionic character is plotted against electronegativity difference $(X_A–X_B)$. The shape of the curve would look like:

• A. $A$
• B. $B$
• C. $C$
• D. $D$

Answer 1

The correct option is C $C$

$50$% ionic character occurs when the electronegativity difference between the atoms is equal to $1.7$. This is evident from curve $C$ and hence is the most appropriate.

$\Delta E.N.=1.7\Rightarrow$ 50% ionic and 50% covalent
$\Delta E.N.>1.7\Rightarrow$ more than 50% ionic and less than 50% covalent
$\Delta E.N.<1.7\Rightarrow$ less than 50% ionic and more than 50% covalent

Hence, option C is correct.