Question

For an ideal transformer:

• A. Output power $=$ Input power
• B. Efficiency is $100\%$
• C. $\frac{V_s}{V_p}=\frac{I_p}{I_s}$
• D. All of these

Answer 1

The correct option is D All of these

D

An ideal transformer is an imaginary transformer which does not have any loss in it, means no core losses, copper losses and any other losses in the transformer. The efficiency of this transformer is considered as $100$. Since there is no losses the output power and input power are equal.

Also,

$\frac{V_s}{V_p}=\frac{I_p}{I_s}$