Question

For the arrangement shown in the figure, the tension in the string is

• A. 6 N
• B. 6.4 N
• C. 0.4 N
• D. Zero

Answer 1

The correct option is D Zero

$mg\sin \theta =1\times 10\times \sin \left(27.89\right)$

$=4.67N$

$mg\cos \theta =0.8\times 10\times \cos \left(27.89\right)$

$=7.07N$

$\because f_{s}mx7mg\sin \theta$

$\therefore$ no tension in string

Hence,

Option $D$ is correct answer.